One corner of a triangle is 3 less than the other and 15 more than the third. Find each corner arithmetically.

Let’s say that one corner of the triangle is x °.

Then, according to the condition of the problem, the second angle will be equal to 3 * x °, and the third, respectively, x – 15 °.

As you know, the sum of all the angles of any triangle is 180 °, which means that, according to the condition of this problem, we can compose the following equation:

x + 3 * x + x – 15 = 180,

5 * x – 15 = 180,

5 * x = 195,

x = 195: 5,

x = 39.

Thus, one angle of the triangle is 39 °, the second 39 * 3 = 117 °, and the third 39 – 15 = 24 °.

Answer: 39 °, 117 ° and 24 °.