One side of the rectangle is 8 cm and the adjacent one is 4 times larger. Find the perimeter of the rectangle.

Let’s write down the condition of the problem:

One side of the rectangle is 8 cm.

The adjacent side of the rectangle is 4 times larger than the first.

The perimeter of the rectangle is? cm.

Comments on the solution:

In this problem, the sides of the rectangle are not named length and width, the words are used here: one side and an adjacent side. These definitions of lengths are equivalent to length and width.

To determine the perimeter, we first calculate the length of the adjacent side by multiplying one side by 4, since the adjacent side is 4 times larger.

By adding twice the number of both sides (one and the adjacent), we find the perimeter.

1) 8 * 4 = 32 (cm) – the length of the adjacent side of the rectangle.

2) 8 * 2 + 32 * 2 = 16 + 64 = 80 (cm) – the perimeter of the rectangle.

Answer: 80 cm.



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