Point A is marked in the MPK triangle on the MK side, point C on the PK side, and, AC || MP. Find the length of the segment AC, if MK = 20 cm, AM = 8 cm, MR = 15 cm
By condition, AC is parallel to MP, and since a straight line parallel to the side of the triangle cuts off a similar triangle from it, the triangles PMK and ACK are similar.
Since the ratio of the similar sides of such triangles is equal, you can make an equality:
MР / AC = MK / AK.
We find the length of the AK from the condition:
AK = MK – AM = 20 – 8 = 12 cm.
AC = MР * AK / MK = 15 * 12/20 = 9 m.
Answer: AC = 9 cm.
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