Prove that in an isosceles triangle the medians drawn from the vertices of the base are equal.

In the triangle ABC, CP and AO are medians;

The ABO triangle is equal to the HРВ triangle on two sides and the angle between them:

BC = AB, since the triangle is isosceles;

ВР = ОВ – half equal sides;

angle B is common.

So AO = CP;

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