Spring rate k = 1000 h / m. the spring is compressed by l = 0.080 m. determine the potential
| July 24, 2021 | education
Spring rate k = 1000 h / m. the spring is compressed by l = 0.080 m. determine the potential energy of elastic deformation of the spring.
Data: k (stiffness of the considered spring) = 1000 N / m; l (spring compression value) = 0.08 m.
The potential energy of elastic deformation of the spring taken can be determined by the formula: En = k * l ^ 2/2.
Calculation: En = 1000 * 0.08 ^ 2/2 = 3.2 J.
Answer: The potential energy of elastic deformation of the taken spring is 3.2 J.
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