Technical fat with a fat mass fraction of 85 percent was subjected to hydrolysis. Received 5.88 kg

Technical fat with a fat mass fraction of 85 percent was subjected to hydrolysis. Received 5.88 kg of glycerin calculate the mass of technical fat if the molecular weight of glycerin is 92, the molecular weight of fat is 890.

Given:
ω (fat) = 85%
m (glycerin) = 5.88 kg = 5880 g
Mr (glycerin) = 92
Mr (fat) = 890

Find:
m tech. (fat) -?

Solution:
1) fat + 3H2O -> glycerin + 3fat acid;
2) n (glycerol) = m (glycerol) / M (glycerol) = 5880/92 = 63.913 mol;
3) n (fat) = n (glycerol) = 63.913 mol;
4) m clean. (fat) = n (fat) * M (fat) = 63.913 * 890 = 56882.57 g;
5) m tech. (fat) = m pure. (fat) * 100% / ω (fat) = 56882.57 * 100% / 85% = 66920.67 g = 66.92 kg.

Answer: The mass of technical fat is 66.92 kg.




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