The 6610kg tractor has a support area of both tracks of 1.4 m2. How much pressure does the tractor apply to the soil?

The force acting on the support platform will be equal to the gravity of the tractor: F = m * g,
where m is the mass of the tractor, g is the acceleration of gravity.
By definition of pressure P = F / S where F is the force, S is the area.
Then we get:
P = F / S = m * g / S = 6610 * 9.8 / 1.4 = 47000 Pa = 47 KPa.

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