The angle between the heights of the parallelogram drawn from one vertex is 125 degrees.

The angle between the heights of the parallelogram drawn from one vertex is 125 degrees. Find the angles of the parallelogram.

Draw two heights from the top of the acute angle, AH and AK.

Let’s designate the angle BAD = X0.

In the resulting quadrangle АHСK, the angle HАК = 125, the angles АHС and АКС = 90, as heights, the angle HСK = X, as opposed to the angle BAD. The sum of these angles is 360.

360 = 125 + 90 + X + 90.

X = 55.

Angle BAD = BCD = 55.

Since the sum of the adjacent angles of the parallelogram is 180, the angle ABC = ADC = 180 – 55 = 125.

Answer: The angles of the parallelogram are 55 and 125 degrees.