The condition says that the sum of the angles at the base of an isosceles triangle is 90 °. In order to find the outer corners of this triangle, let’s first find the inner corners of the triangle.
So, the sum of the angles of a triangle is 180 °. We are looking for the degree measure of the third angle:
180 ° – 90 ° = 90 ° apex angle.
90 °: 2 = 45 ° angles at the base.
The sum of adjacent angles is 180 °.
180 ° – 90 ° = 90 ° outside angle at the apex of the triangle;
180 ° – 45 ° = 135 ° outside angles at each of their angles at the base of the triangle.
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