The aquarium has the shape of a parallelepiped with a base of 0.4 * 0.2 m filled with water

The aquarium has the shape of a parallelepiped with a base of 0.4 * 0.2 m filled with water to a height of 0.15. Determine the volume of water in the aquarium. What is the mass of this water. the density of this water is 1000 kg / m3

1) Let’s calculate the volume of water in the aquarium.

V = a * b * c, where according to the condition a * b are the dimensions of the base of the aquarium (a = 0.4 m; b = 0.2 m), c is the height of the water in the aquarium (c = 0.15 m).

Let’s do the calculation:

V = 0.4 * 0.2 * 0.15 = 0.012 m3.

2) Calculate the mass of water in the aquarium:

m = ρ * V, where, according to the condition, ρ is the density of water in the aquarium (ρ = 1000 kg / m3).

Let’s perform the calculation:

m = 1000 * 0.012 = 12 kg.

Answer: The aquarium contains water with a volume of 0.012 m3 and a mass of 12 kg.