The area of a triangle is 52 cm2 larger than the area of a similar triangle. The perimeter of the smaller triangle refers to the perimeter of the larger triangle as 6: 7. Determine the area of the smaller of these triangles.
We are given two triangles that are similar to each other.
It is also known that the area of one triangle is 52 cm ^ 2 larger than the area of the second triangle.
Let’s start by writing down the area of the second triangle:
S2 = S1 + 52,
Perimeters are 6: 7:
P1 / P2 = 6/7.
It is known that in such triangles the areas are referred to as squares of similar sides (in our case, the perimeters.
Writes the ratio:
S1 / S2 = P1 ^ 2 / P2 ^ 2,
S1 / (S1 + 52) = 36/49;
S1 = 144 cm ^ 2, S2 = 169 cm ^ 2.
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