The area of the isosceles triangle ABC with the base of the AC is 4800 cm2.

The area of the isosceles triangle ABC with the base of the AC is 4800 cm2. Find the heights drawn to the sides of the triangle if AB = 100cm.

1. Vertices of triangle A, B, C. CE and AK – heights. AB = BC = 100 centimeters.

2. We calculate the length of the height CE, using the formula for calculating the area (S) of a given triangle:

S = AB x CE / 2 = 100 x CE / 2 = 4800 centimeters².

CE = 2S / 100 = 2 x 4800/100 = 96 centimeters.

3. We calculate the length of the height of the AK using another formula for calculating the area of a triangle:

S = BC x AK / 2.

AK = 2S / BC = 2 x 4800/100 = 96 centimeters.

Answer: AK = CE = 96 centimeters.




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