The area of the rectangle is 108 cm2. Its length is 12 cm greater than the width. Find the width of the rectangle.

The area of the rectangle is 108 cm2. Its length is 12 cm greater than the width. Find the width of the rectangle. Find its length.

We draw up an equation in which we write the width of the rectangle as x cm.

Since its length is 12 cm longer, it will be equal to: x + 12 cm.

Since the area of a rectangle is the product of its sides, we get the following expression:

x * (x + 12) = 108.

x ^ 2 + 12 * x = 108.

We get a quadratic equation:

x ^ 2 + 12 * x – 108 = 0.

D ^ 2 = (12) ^ 2 – 4 * 1 * (-108) = 144 + 432 = 576.

D = √576 = 24.

x = (-12 + 24) / 2 = 12/2 = 6 cm (rectangle width).

x + 12 = 6 + 12 = 18 cm (length).

Answer: 6 and 18 cm.