The area of the square is 64 cm2. Find the area of a rectangle, the perimeter of which is equal

The area of the square is 64 cm2. Find the area of a rectangle, the perimeter of which is equal to the perimeter of the given square, if one of its sides is 3 times larger than the other.

Let’s find what the side of the square is equal to:

√64 = 8 (cm) – side of the square.

2) Find the perimeter of the square:

8 × 4 = 32 (cm) – perimeter of the square.

3) The perimeter of the rectangle is also 32 cm.

Let’s find its sides using the equation.

Let one side of the rectangle be x, then the other is 3x.

Then:

(x + 3x) × 2 = 32;

4x = 32: 2:

4x = 16;

x = 16: 4;

x = 4;

3x = 3 × 4 = 12.

Answer: the sides of the rectangle are 4 cm and 12 cm.