The arrow is fired from the bow vertically upward at a speed of 10 m / s. What is the maximum height it rises?

To find the maximum lift for a given boom, apply the formula: S = h = (V0 ^ 2 – V ^ 2) / 2a = (V0 ^ 2 – 0 ^ 2) / 2g = V0 ^ 2 / 2g.

Variables and constants: V0 – speed at the moment of starting (V0 = 10 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: h = V0 ^ 2 / 2g = 10 ^ 2 / (2 * 10) = 5 m.

Check (the law of conservation of energy): m * g * h = m * V ^ 2/2, whence we express: h = V ^ 2 / (g * 2) = 10 ^ 2 / (10 * 2) = 5 m (true ).

Answer: The maximum lift for a given boom is 5 m.



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