The arrow was fired straight up from the bow. How much did the boom speed decrease in the second second of ascent?
| September 20, 2021 | education
To find the decrease in the speed of the released arrow in the second second of ascent, we will use the formula: ΔV = V1 – V2 = (V0 – g * t1) – (V0 – g * t2) = g * (t2 – t1).
Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); t2 – considered time (t2 = 2 s); t1 – start time (t1 = 1 s).
Calculation: ΔV = 10 * (2 – 1) = 10 m / s.
Answer: In the second second of ascent, the speed of the fired arrow decreased by 10 m / s.
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