The artificial satellite revolves around the Earth in a circular orbit at an altitude of H = 3200 km

The artificial satellite revolves around the Earth in a circular orbit at an altitude of H = 3200 km above the Earth’s surface. The linear velocity of the satellite will be ..

Data: H (height above the surface) = 3200 km = 32 * 10 ^ 5 m; G (gravitational constant) ≈ 6.67 * 10 ^ -11 m2 / (s2 * kg); Rz (radius of the Earth) = 6371 * 10 ^ 3 m; Mz (mass of the Earth) = 5.9726 * 10 ^ 24 kg.
The speed of the artificial satellite: V = √ (G * Ms / (Rs + H)) = √ (6.67 * 10 ^ -11 * 5.9726 * 10 ^ 24 / (6371 * 10 ^ 3 + 32 * 10 ^ 5 )) = 6451.6 m / s ≈ 6.45 km / s.
Answer: the speed is 6.45 km / s.