The average speed of a cyclist on the way was 17 km / h. For the first third of the time, he drove at a speed 3 km / h more than the remaining time. Find the speed of the cyclist at each of the two legs of the path.
It follows from the problem statement that the cyclist covered the first third of the way faster than the second and third third of the way. The speed of movement on the second and third third of the path is the same, let it be – x. Then the first third will be expressed as 3 + x. Knowing that the average speed of a cyclist is 17 km / h, the following equation can be drawn up.
((3 + x) + x + x) / 3 = 17
3 + 3x = 17 * 3
3 + 3x = 51
3x = 51 – 3
3x = 48
x = 48/3
x = 16
This means that the speed on the remaining section of the road was 16 km / h. Now let’s calculate the speed of the cyclist in the first third of the section.
16 + 3 = 19 km / h.
Answer: At the first stage of the journey, the speed is 19 km / h, on the remaining distance – 16 km / h.
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