The BCD triangle is isosceles. Straight. parallel to base DB, intersects sides BC and CD at points M

The BCD triangle is isosceles. Straight. parallel to base DB, intersects sides BC and CD at points M and K. Prove that CK = CM.

The straight line MK cuts off a similar triangle CMK from the triangle BCD, and in such triangles the aspect ratio is equal, respectively.

ВС: СD = 1, which means that in the triangle MSC – СK: СМ = 1, which means that СМ = СK, which was required to prove.




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