Angle АLC is the outer angle of triangle ABL, then its value is equal to the sum of two inner, not adjacent angles.
Angle ALC = BAL + ABL, then angle BAL = ALC – ABL = 112 – 106 = 6.
Since, by condition, AL is the bisector of angle A, then the angle CAL = BAL = 6.
In triangle ACL, angle ACL = 180 – ALC – CAL = 180 – 112 – 6 = 62.
Angle ACB = ACL = 62.
Answer: Angle ABC is 62.
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