The body falls freely from a height of 200 m. What path will the body cover in the second half of the time?

Task data: h (body fall height) = 200 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The duration of the entire fall: h = g * t ^ 2/2, whence t = √ (h * 2 / g) = √ (200 * 2/10) = 6.324 s.

2) Path for the first half of the time: h1 = g * (t / 2) ^ 2/2 = 10 * (6.324 / 2) ^ 2/2 = 50 m.

3) Path in the second half of the time: h2 = h – h1 = 200 – 50 = 150 m.

Check: h2 = V0 * t / 2 + g * (t / 2) ^ 2/2 = (g * t / 2) * t / 2 + g * (t / 2) ^ 2/2 = 3 * g * (t / 2) ^ 2/2 = 3 * 10 * (6,324 / 2) ^ 2/2 = 150 m.

Answer: In the second half of the time, the body will fly 150 meters.