The body falls from a height of 490 m. Determine its speed at the moment it reaches the Earth’s surface.

Data: h (the height from which the body in question began its fall) = 490 m; the fall will be considered free (V0 (velocity at the beginning of the fall) = 0 m / s).

Constants: g (acceleration due to gravity) = 9.8 m / s2.

The speed at the moment the body under consideration reaches the Earth’s surface can be expressed from the formula: S = h = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2g and V = √ (2g * S). Also, the speed could be expressed from the equality: Ek = En.

Calculation: V = √ (2 * 9.8 * 490) = 98 m / s.

Answer: The speed of the body will be equal to 98 m / s.

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