# The body moves in a straight line. Under the action of a constant force of 2 H in 3 s, the modulus of the body’s

March 25, 2021 | education

| **The body moves in a straight line. Under the action of a constant force of 2 H in 3 s, the modulus of the body’s momentum increased and became equal to 15 kg * m / s. The initial impulse of the body is.**

To calculate the initial impulse of a given body, we use the equality: F * t = P2 – P1, whence we express: P1 = P2 – F * t.

Values of variables: P2 – final impulse of the body (P2 = 15 kg * m / s); F – constant force (F = 2 N); t – elapsed time (t = 3 s).

Calculation: P1 = P2 – F * t = 15 – 2 * 3 = 9 kg * m / s.

Answer: The initial impulse of a given body was equal to 9 kg * m / s.

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