# The box is pulled evenly with a rope directed at an angle of 30 to the direction of the box’s speed.

**The box is pulled evenly with a rope directed at an angle of 30 to the direction of the box’s speed. The pulling force of the rope is 50 N. After performing the work of 866 J, the box was pulled over a distance equal to ..**

∠α = 30 °.

F = 50 N.

A = 866 J.

S -?

The mechanical work A of the force F is determined by the formula: A = F * S * cosα, where S is the displacement of the body under the action of the force, ∠α is the angle between the direction of the force F and displacement S.

Since the movement of the box S coincides with the direction of its velocity V, then ∠α – will be the angle between F and S.

Let us express the movement of the box: S = A / F * cosα.

S = 866 J / 50 N * cos30 ° = 20 m.

Answer: under the action of force, the box was pulled over a distance of S = 20 m.