The breaking strength of the rope is 1600 N. What is the maximum mass of the load that can be lifted

The breaking strength of the rope is 1600 N. What is the maximum mass of the load that can be lifted with this rope with an acceleration of 15 m / s ^ 2.

Given:

T = 1600 Newton – tensile strength of the rope;

a = 15 m / s ^ 2 – acceleration;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the mass m (kilogram) of the load that can be lifted by this rope with acceleration a.

According to Newton’s second law:

T – F gravity = m * a;

T – m * g = m * a;

T = m * a + m * g;

T = m * (a + g);

m = T / (a + g) = 1600 / (10 + 15) = 1600/25 = 64 kilograms.

Answer: with the help of this rope with an acceleration of 15 m / s ^ 2, you can lift a maximum load equal to 64 kilograms.