The breaking strength of the rope is 1600 N. What is the maximum mass of the load that can be lifted with this rope with an acceleration of 15 m / s ^ 2.
T = 1600 Newton – tensile strength of the rope;
a = 15 m / s ^ 2 – acceleration;
g = 10 m / s ^ 2 – acceleration of gravity.
It is required to determine the mass m (kilogram) of the load that can be lifted by this rope with acceleration a.
According to Newton’s second law:
T – F gravity = m * a;
T – m * g = m * a;
T = m * a + m * g;
T = m * (a + g);
m = T / (a + g) = 1600 / (10 + 15) = 1600/25 = 64 kilograms.
Answer: with the help of this rope with an acceleration of 15 m / s ^ 2, you can lift a maximum load equal to 64 kilograms.
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