The car drove twice along the 109 km long ring road. what is the restraint of the car, what is its mixing?

Let’s say the car started moving from point A, which is located on the ring road with a length of 109 km. Since he passed it twice, the distance covered is equal to twice the length of the road: S = 109 * 2 = 218 km. After he passed the road, he again returned to point A, from which he began to move. Therefore, its movement will be 0.

Answer: the distance traveled is 218 km, the displacement is 0 km.

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