The car had a load that was 4/5 of its carrying capacity. At the first stop, 1/6 of the cargo was unloaded

The car had a load that was 4/5 of its carrying capacity. At the first stop, 1/6 of the cargo was unloaded, and at the second, 1/3 of its carrying capacity was loaded. At the third stop, 2/3 of the brought cargo was unloaded. 5 tons were brought to the final destination. What is the carrying capacity of the car?

Let x be the carrying capacity of the machine.
The car set off with a load – 4 / 5x.
First stop – subtract 1/6 * 4 / 5x = 4 / 30x.
Second, add 1/3x.
The third – we subtract from the brought 2/3 * (4 / 5x – 4 / 30x + 1 / 3x) = 2/3 * (24 / 30x – 4 / 30x + 10 / 30x)
= 2 / 3x.
Drove – 5 tons.
4 / 5x – 4 / 30x + 1 / 3x – 2 / 3x = 5.
24x – 4x + 10x – 20x = 150.
10x = 150.
x = 15.
Answer: The car can carry 15 tons.