The car, moving at a speed of 15 m / s, began to skid under heavy braking. Determine the path that the car will

The car, moving at a speed of 15 m / s, began to skid under heavy braking. Determine the path that the car will cover in wet weather if the coefficient of sliding friction of wheels on the asphalt u = 0.5 (The movement is considered equally slow)

V0 = 15 m / s.

V = 0 m / s.

μ = 0.5.

g = 9.8 m / s2.

S -?

When braking with constant acceleration, the path S traversed by the body will be determined by the formula: S = (V0 ^ 2 – V ^ 2) / 2 * a, where V0, V are the initial and final vehicle speed, a is the body’s acceleration.

Since the car has stopped, V = 0 m / s.

S = V0 ^ 2/2 * a.

When braking, the car moves only under the influence of sliding friction force.

m * a = Ftr.

Ftr = μ * m * g.

a = μ * g.

S = V0 ^ 2/2 * μ * g.

S = (15 m / s) ^ 2/2 * 0.5 * 9.8 m / s2 = 23 m.

Answer: in case of emergency braking, the vehicle’s path will be S = 23 m.