The car starts off with an acceleration of 0.2 ms2 and reaches a speed of 18 km / h. Determine the work done by the car in this area, if the traction force is 3 kN
a = 0.2 m / s2.
V0 = 0 m / s.
V = 18 km / h = 5 m / s.
Ft = 3 kN = 3000 N.
We express the work of the traction force of the car Am by the formula: At = Ft * S * cosα. Since the direction of the traction force Ft of the car coincides with the direction of its movement, then ∠α = 0 °.
We express the movement of the car S by the formula: S = (V ^ 2 – V0 ^ 2) / 2 * a.
Since the car starts to move V0 = 0 m / s, the formula will take the form: S = V ^ 2/2 * a.
Am = Ft * V ^ 2/2 * a.
Am = 3000 N * (5 m / s) ^ 2/2 * 0.2 m / s2 = 187500 J.
Answer: on the site, the car does work Am = 187500 J.
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