The chord subtracts a 140-degree arc. At what angle is this chord visible from any point on the larger

The chord subtracts a 140-degree arc. At what angle is this chord visible from any point on the larger arc into which the chord divides the circle?

Since the chord contracts the circular arc at 140, the central angle resting on the chord is also 140. The angle MNO = 140.

Then the inscribed angle will be equal to half of the central angle. MNB = MNB1 = MNB2 = MNB3 = MON / 2 = 140/2 = 70.

Answer: From any point on the larger arc, the chord is seen at an angle of 70.