# The circuit section consists of two series-connected conductors, the resistance of which is 40 and 60 ohms.

The circuit section consists of two series-connected conductors, the resistance of which is 40 and 60 ohms. The voltage on the section of the circuit is 60V. What amount of heat will be released in each of the resistors in 1 min?

R1 = 40 ohms.

R2 = 60 ohms.

U = 60 V.

t = 1 min = 60 s.

Q1 -?

Q2 -?

The amount of heat Q, which is released in a conductor with current, is determined by the formula of the Joule-Lenz law: Q = I2 * R * t.

Q1 = I1 ^ 2 * R1 * t.

Q2 = I2 ^ 2 * R2 * t.

With a series connection of conductors, the current I in all conductors is the same: I = I1 = I2, and the total resistance R is the sum: R = R1 + R2.

We find the current strength according to Ohm’s law for a section of the circuit: I = U / R = U / (R1 + R2).

I = 60 V / (40 Ohm + 60 Ohm) = 0.6 A.

Q1 = (0.6 A) ^ 2 * 40 Ohm * 60 s = 864 J.

Q2 = (0.6 A) ^ 2 * 60 Ohm * 60 s = 1296 J.

Answer: Q1 = 864 J, Q2 = 1296 J.

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