The circuit section consists of two series-connected conductors with resistance R1 = 6 ohms and R2

The circuit section consists of two series-connected conductors with resistance R1 = 6 ohms and R2 = 2 ohms. Determine the amperage and total voltage of this section of the circuit. R1 voltage is 24V

First, you need to determine the strength of the current that flows through the first resistance.

According to Ohm’s law, for this we divide the known mains voltage by the known resistance value.

Thus, we get:

24/6 = 4 A.

Since the resistances are connected in series, then the total resistance in the circuit section will be equal to their sum, namely:

6 + 2 = 8 ohms.

We find the total voltage of the network.

To do this, we multiply the total resistance of the section by the current that flows.

We get:

U = 8 * 4 = 32 V.

Answer:

4 A, 32 V.