The conveyor evenly lifts a load weighing 190 kg to a height of 9 meters in 50 seconds.

| September 23, 2021 | education

The conveyor evenly lifts a load weighing 190 kg to a height of 9 meters in 50 seconds. Determine the current in the electric motor if the voltage in the electrical network is 380V. Conveyor motor efficiency is 60%

To determine the value of the current in the electric motor of the used conveyor, we apply the formula: η = Apol / Qzatr = m * g * h / (U * I * t), from where we can express: I = m * g * h / (η * U * t).

Constants and variables: m – weight of the cargo (m = 190 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); h is the height of the lifting of the load (h = 9 m); U – mains voltage (U = 380 V); η – engine efficiency (η = 60% = 0.6); t – the duration of the conveyor (t = 50 s).

Calculation: I = m * g * h / (η * U * t) = 190 * 9.8 * 9 / (0.6 * 380 * 50) = 1.47 A.

Answer: The current in the electric motor of the used conveyor is 1.47 A.



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