The corners AOB and BOC are adjacent. The DO beam is perpendicular to the BO beam and divides the BOC angle into two angles. Find the angle AOB if the angle COD = 50 °
The sum of the adjacent angles of a triangle (or AOC) is 180 °. Then:
angle AOB = angle AOC – (angle BOC + angle COD)
We know the COD angle from the problem statement. And the third angle (BOD) is formed by the perpendicular DO to the BO beam, so it will be right, and its degree measure = 90 °.
Angle AOB = 180 ° – (90 ° + 50 °) = 40 °
Answer: 40 °.
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