The current in the circuit is 0.5 A, where 6 identical lamps are connected in parallel. Find the resistance of the lamp if U is 220 V.
Task data: I (current in the created circuit) = 0.5 A; n (number of identical lamps) = 6 lamps; U (mains voltage) = 220 V; parallel connection.
1) Total resistance of the created circuit: R = U / I = 220 / 0.5 = 440 Ohm.
2) Resistance of one lamp: R = R1 / n, whence R1 = R * n = 440 * 6 = 2640 Ohm = 2.64 kOhm.
Answer: The resistance of each of the identical lamps is 2.64 kOhm.
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