The current strength in a conductor 20 cm long with a mass of 4 g is equal to 10A. Find the induction of the magnetic

The current strength in a conductor 20 cm long with a mass of 4 g is equal to 10A. Find the induction of the magnetic field so that the force of gravity balances the force of the ampere.

Task data: l (conductor length) = 20 cm (in SI system l = 0.2 m); m (conductor mass) = 4 g (in SI m = 0.004 kg); I (current) = 10 A.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To find the required magnetic field induction, we will use the equality: Fa = Fт and B * I * l = m * g, whence B = m * g / (I * l).

Let’s make a calculation: B = 0.004 * 10 / (10 * 0.2) = 0.02 T.

Answer: To keep the conductor in equilibrium, the magnetic field induction must be 0.02 T.