The cyclist descends the mountain with an acceleration of 0.5 m / s2. what will be his speed in 30 s, if the initial speed of the cyclist is 3 m / s
To determine the value of the speed of the presented cyclist after 30 seconds of accelerated descent, we will use the formula: V = Vн + a * t.
Data: Vн – speed before descent (Vн = 3 m / s); a – constant acceleration (a = 0.5 m / s2); t is the considered duration of the descent (t = 30 s).
Let’s calculate: V = 3 + 0.5 * 30 = 18 m / s.
Answer: After 30 seconds of rapid descent, the speed of the presented cyclist will be equal to 18 m / s.
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