# The cyclist left the hill in 1 minute, moving with an acceleration of 0.5 m / s2.

March 25, 2021 | education

| **The cyclist left the hill in 1 minute, moving with an acceleration of 0.5 m / s2. Determine the length of the hill if the initial speed of the cyclist is 28 km / h.**

t = 1 min = 60 s.

V0 = 28 km / h = 7.8 m / s.

a = 0.5 m / s2.

S -?

Since the cyclist moves down the hill at uniform acceleration, we can express his path by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the speed at the beginning of the hill, t is the time the cyclist moves, a is the acceleration of the cyclist when moving.

Substitute the data from the problem statement into the formula: S = 7.8 m / s * 60 s + 0.5 m / s2 * (60 s) ^ 2/2 = 468 m + 900 m = 1368 m.

Answer: the length of the slide along which the cyclist was moving was S = 1368 m.

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