The diagonals of rectangle ABCD meet at point O. Find the perimeter of triangle AOD if AB = 9, BC = 12, BD = 15.

We will use the property of the rectangle diagonals, which are equal to each other, and are divided in half at the point of intersection, then BD = AC, and AO = CO = BO = DO = 15/2 = 7.5 cm.

The opposite sides of a rectangle are equal, then AD = BC = 12 cm.

Then Raod = AO + DO + AD = 7.5 + 7.5 + 12 = 27 cm.

Answer: The perimeter of the triangle AOD is 27 cm.



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