The diagonals of the parallelogram ABCD are 5 cm and 7 cm, the side of the BC is 4 cm. Find the perimeter of the ADK triangle where K is the intersection point of the diagonals.
The solution of the problem:
Side AD = BC = 4 cm.
The diagonals of the parallelogram are halved at the intersection.
AK = KС = AC / 2;
AK = 7/2 = 3.5 cm.
ВK = KD = BD / 2;
ВK = 5/2 = 2.5 cm.
Let’s define the perimeter P of the triangle AKD.
P = AD + AK + KD;
P = 4 + 3.5 + 2.5 = 10 cm.
Answer: The perimeter of triangle AKD is 10 cm.
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