1. The probability of the event Ai that three points will be dropped on the i-th throw of the dice:
P (Ai) = 1/6.
2. Accordingly, the probability of the opposite event Ai ‘- not getting three points:
P (Ai ‘) = 1 – P (Ai);
P (Ai ‘) = 1 – 1/6 = 5/6.
3. The probability of the event B1 that three points will be rolled on the first roll of the dice:
P (B1) = P (A1) = 1/6.
4. Probability of B2 event that the first time three points are rolled on the second throw:
P (B2) = P (A1 ‘) * P (A2 | A1’);
P (B2) = 5/6 * 1/6 = 5/36.
5. The probability of the event S2 that three points will be rolled on the first two throws:
P (S2) = P (B1) + P (B2);
P (S2) = 1/6 + 5/36 = 11/36.
6. The likelihood of the opposite event S2 ‘that the first two throws do not drop three points:
P (S2 ‘) = 1 – P (S2);
P (S2 ‘) = 1 – 11/36 = 25/36 ≈ 0.6944.
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