# The dihedral angle is 120 ° degrees. Inside it, point A is given, which is located at a distance of 24 cm

**The dihedral angle is 120 ° degrees. Inside it, point A is given, which is located at a distance of 24 cm from both edges of the corner. What is the distance from point A to the edge of the dihedral angle?**

From point A, construct perpendiculars AB and AC to the faces of the dihedral angle.

Then the angle ABO = ASO = 90, and therefore the triangles AOB and AOC are rectangular.

By condition, the lengths of the segments AB = AC = 24 cm.

Then, in the right-angled triangles AOB and AOS, the hypotenuse of AO is common, and the legs AB and AC are equal to each other, which means that the right-angled triangles AOB and AOC are equal in leg and hypotenuse, the fourth sign of equality of right-angled triangles.

Then the angle AOB = AOC = BOC / 2 = 120/2 = 600.

In a right-angled triangle AOB, Sin AOB = AB / AO.

AO = AB / Sin AOB = 24 / Sin60 = 24 / (√3 / 2) = 48 / √3 = 16 * √3 cm.

Answer: From point A to the edge of the dihedral angle 16 * √3 cm.