The distance between stations A and B is 36 km. From station A to station B two cyclists set off simultaneously
The distance between stations A and B is 36 km. From station A to station B two cyclists set off simultaneously. The speed of the first cyclist is 12 km / h, the speed of the second is 3 km / h less. How many hours earlier than the second, the first cyclist will arrive at station B. ?
The solution of the problem:
1. Find in the first action in how many hours the first cyclist whose speed is 12 kilometers per hour will arrive at station B.
36/12 = 3 hours
2. Let’s calculate the speed of the second cyclist per hour.
12-3 = 9 kilometers
3. Determine how long it will take for the second cyclist to arrive at station B.
36/9 = 4 hours
4. Find out how many hours before the second the first cyclist will arrive at the station.
4-3 = 1 hour
Answer: The first cyclist will arrive at the station one hour earlier than the second cyclist.