The diver sank into the sea to a depth of 60m. With what force does the water squeeze the surface

The diver sank into the sea to a depth of 60m. With what force does the water squeeze the surface of a diver’s spacesuit if its surface area is 2.5 m2?

Initial data: h (depth to which the diver sank) = 60 m; S (surface area of the diver’s spacesuit) = 2.5 m2.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2; ρ (density of seawater) = 1030 kg / m3.

The force with which the sea water squeezes the surface of the suit, we determine from the equality: ρ * g * h = P = F / S, whence F = S * ρ * g * h.

Let’s make a calculation: F = 2.5 * 1030 * 10 * 60 = 1545000 N (1545 kN).

Answer: Sea water compresses the surface of the suit with a force of 1545 kN.