The elastic force arising from the deformation of the spring is 20 N. The spring rate is 200 N / m.
| October 12, 2021 | education
The elastic force arising from the deformation of the spring is 20 N. The spring rate is 200 N / m. The deformation of the spring is …
Task data: Fcont. (the elastic force that arose during the deformation of the spring) = 20 N; k (stiffness of the considered spring) = 200 N / m.
The deformation of the spring is equal to the ratio of the generated elastic force and the stiffness of the spring itself: Δx = Fcont. / k.
Calculation: Δx = 20/200 = 0.1 m or 10 cm.
Answer: The deformation of the spring is 0.1 m (10 cm).
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