The electric field moves a positive charge of 3 * 10 ^ -7 C between points with potentials of 200 V and 120 V what kind of work does the electric field do in this case.
q = 3 * 10 ^ -7 Cl.
φ1 = 200 V.
φ2 = 120 V.
The work A of the electrostatic field to move the charge from one point to another is determined by the formula: A = q * (φ1 – φ2), where q is the magnitude of the charge that is moved, φ1 is the potential of the electric field at the first point, φ2 is the potential of the electric field in the second point.
A = 3 * 10 ^ -7 Cl * (200 V – 120 V) = 240 * 10 ^ -7 J.
Answer: the work of the electric field is A = 240 * 10 ^ -7 J.
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