The first spring has a stiffness of 20N / m. Second 40n / m. The ratio of the potential energy of the second spring
| July 27, 2021 | education
The first spring has a stiffness of 20N / m. Second 40n / m. The ratio of the potential energy of the second spring to the potential energy of the first E2 / E1 is equal to.
Initial data: k1 (stiffness of the first spring) = 20 N / m; k2 (stiffness of the second spring) = 40 N / m.
The ratio of the potential energy of the second spring to the first one is determined by the formula: n = En2 / En1 = 0.5 * k2 * Δx ^ 2 / (0.5 * k2 * Δx ^ 2) = k2 / k1 = 40/20 = 2.
Answer: 2. The ratio of the potential energies of the springs is 2.
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