The frequency range of the grand piano is from 9 to 90000 Hz. Find the range of sound waves in the air

v1 = 9 Hz.

v2 = 90,000 Hz.

Vsv = 340 m / s.

λ1 -?

λ2 -?

The frequency of the sound wave v is related to the wavelength λ by the formula: Vsv = v * λ, where Vsv is the speed of the sound wave.

λ1 = Vev / v1.

λ1 = 340 m / s / 9 Hz = 37.7 m.

λ2 = Vev / v2.

λ2 = 340 m / s / 90,000 Hz = 0.0037 m.

Answer: λ1 = 37.7 m, λ2 = 0.0037 m.



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