The gas occupies a volume of V₁ = 2m₃ at a temperature of t₁ = 273 * C. What will its volume be at a temperature of 546 * C and the same pressure.
V1 = 2 cubic meters – initial gas volume;
T1 = 273 degrees Celsius = 546 degrees Kelvin – the initial gas temperature;
T2 = 546 degrees Celsius = 819 degrees Kelvin.
It is required to determine V2 (cubic meter) – the volume of gas at the temperature T2.
Since, according to the condition of the problem, the process occurs at the same pressure (P = const), then:
V1 / T1 = V2 / T2;
V2 = V1 * T2 / T1 = 2 * 819/546 = 1638/546 = 3 cubic meters.
Answer: at a temperature of 546 degrees Celsius, the volume of gas will be 3 cubic meters.
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