# The harvester has a working width of 5 meters. With an average speed of the harvester of 0.5 m / s.

The harvester has a working width of 5 meters. With an average speed of the harvester of 0.5 m / s. Is the area harvested in 10 hours even?

Initial data: L (working width of the combine) = 5 m; V (average speed of the combine) = 0.5 m / s; t (working time of the combine) = 10 hours.

SI system: t = 10 h = 10 * 3600 = 36,000 s.

1) Since the average speed of the combine is 0.5 m / s, the combine will cover the distance l = 0.5 m in 1 s.

2) The area of the harvested area in 1 s: S = L * l = 5 * 0.5 = 2.5 m ^ 2.

3) The area of the harvested area in 10 hours: S10 = S * t = 2.5 * 36000 = 90,000 m ^ 2 = 9 hectares.

Answer: In 10 hours, the harvester will be able to harvest 9 hectares.

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